Light work: Exerting up to 20 pounds of force occasionally and/or a
negligible amount of force constantly to move objects. Sitting, standing,
walking, talking, hearing, keyboarding, and repetitive motions. Close
visual acuity. Position requires sitting and standing for long periods of
time and the ability to speak clearly and effectively for an extended
period of time.
It's that "exerting up to 20 pounds of force occasionally and/or a negligible amount of force constantly to move objects" that caught The Motley Monk's eye.
What possibly could that requirement be communicating to one who might consider applying for this particular job?
To wrap his mind around that concept, The Motley Monk did a little homework, asking: What does that exertion of up to 20 pounds of force look like?
Care of Ron Kurtus over at the School of Champions, here's the answer:
Pressure of solid on a solid
When you apply a force to a solid object, the pressure is defined as
the force applied divided by the area of application. The equation for
P = F/A
- P is the pressure
- F is the applied force
- A is the surface area where the force is applied
- F/A is F divided by A
Visualize force this way:
For example, if you push on an object with your hand with a force
of 20 pounds, and the area of your hand is 10 square inches, then
the pressure you are exerting is 20 / 10 = 2 pounds per square inch.
Pressure equals Force divided by Area
You can see that for a given force, if the surface area is smaller, the
pressure will be greater. If you use a larger area, you are spreading
out the force, and the pressure (or force per unit area) becomes smaller.
At first, The Motley Monk inferred that the successful applicant must be capable of forcing some pretty big egos around (for example, the School's full professors), in the sense of Lou Gerstner's "Who Says Elephants Can't Dance?"
But, Ron Kurtus' example of force provided the definitive answer:
Example with shoes
A good example of how a force on small area can result in a very high
pressure is seen in women's shoes with high spiked heels. These types
of shoes can cause damage to some floors due to the very high pressure
on the floor at the heel.
An average shoe distributes the weight of the person over 20 square
inches. Thus, a 100-pound person applies 100/20 = 5 pounds per square
inch on the floor.
Since a spike-heel is only 0.25 square inches, the 100-pound person
would be applying 100/0.25 = 400 pounds per square inch on the floor
at the heel! In some cases, that is sufficient to damage the floor.
In other words, the successful applicant for the Dean of the Business School at Stevenson University will be a female who possesses the ability to kick those big egos wearing spike-heels!
Why not just say that in the job description?
Let the discussion begin...